How would you use prepared statement ? within quotes?

[mark8044]

Im trying to convert the following string

x[mark8044][userid:12345] into ==> x[newusername][userid:12345]

But something is not working here, I have a feeling it has to do with trying to put the prepared statement ? that sites within a quote '

$userid = 12345;
$oldusername = 'mark8044';
$newusername = 'newusername';



        $db->rawQuery("
                    UPDATE texthistory 
                    SET texthistory = REPLACE(pagetext, 'x['?'][userid:'?']', '@['?'][userid:'?']') 
                    WHERE texthistory LIKE '%@['?'][userid:'?']%' 
                    AND userid = ?", Array($oldusername,$userid,$newusername, $userid, $oldusername, $userid));

Removing the quotes does not seem to work either

        $db->rawQuery("
                    UPDATE texthistory 
                    SET texthistory = REPLACE(pagetext, 'x[?][userid:?]', '@[?][userid:?]') 
                    WHERE texthistory LIKE '%@[?][userid:?]%' 
                    AND userid = ?", Array($oldusername,$userid,$newusername, $userid, $oldusername, $userid));