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Bound the dilogarithm declines by what they allocate rather than a wall clock #2011

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Rafael-SOWNet merged 1 commit into from
Oct 21, 2026
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Bound the dilogarithm declines by what they allocate rather than a wall clock #2011

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9 changes: 7 additions & 2 deletions Sources/Tests/UnitTests/Calculus/ExponentialSubstitutionIntegralTest.cs
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Original file line number Diff line number Diff line change
Expand Up @@ -227,10 +227,15 @@ public void AnInverseFunctionOfAHyperbolicOneTimesARationalFunctionOfThem()
[InlineData("x^2*sech(x)^2")]
public void ADilogarithmIsDeclinedAtOnce(string integrand)
{
var watch = System.Diagnostics.Stopwatch.StartNew();
// Bounded by what the decline allocates, not by a wall clock, which measures the runner:
// on a loaded machine `x^2 sech(x)^2` took 26-58 s against a 20 s bound with its
// allocation unchanged. Measured cold, the four allocate 0.03, 0.04, 0.11 and 1.0 GB;
// the search this guards against ran for twenty-five seconds.
var before = GC.GetAllocatedBytesForCurrentThread();
var integral = integrand.ToEntity().Integrate("x");
var allocated = GC.GetAllocatedBytesForCurrentThread() - before;
Assert.Contains("integral(", integral.Stringize());
Assert.True(watch.ElapsedMilliseconds < 20_000, $"{integrand} took {watch.ElapsedMilliseconds} ms to decline");
Assert.True(allocated < 3_000_000_000L, $"{integrand} allocated {allocated / 1e9:F2} GB to decline");
}

/// <summary>
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